Question

A body of mass 500 g is at rest on a frictionless surface. Calculate the distance travelled by it in 10 second when acted upon by a force of 10^-2 N.

Answer 1

Force = 10^-2 N = 0.01 N  initial velocity, u = 0

mass, m = 500 g = 0.5 kg  distance travelled, s =?    time, t = 10 sec

Force = mass × acceleration 

acceleration, a =\(\frac{force}{mass}\) = \(\frac{0.01}{0.5}\)= 0.02 m/s²

Using the equation, s = ut + \(\frac{1}{2}\) at²

 =0×10+\(\frac{1}{2}\)×0.02×10²= 1