Let the denominator be ‘X’, so the numerator will be ‘(X+1)’.
30(2X2 + 2X + 1) = 61 (X2 + X)
60X2 + 60X + 30 = 61X2+ 61X
X2 + X – 30 = 0–––––– (i)
On applying Sreedhracharya formula
X = – 6 or 5
∴ X = 5 (Only positive values)
∴ Denominator is = 5 & numerator is (X+1) = 6
∴ The fraction is 6/5.