Question

A constant force acts on an object of mass 10 kg for a duration of 4 s. It increases the objects velocity from 2 ms^-1 to 8 ms^-1 . Find the magnitude of the applied force.

Answer 1

Mass of an object m = 10 kg

initial velocity u = 2 ms^-1

Final velocity v = 8 ms^-1

We know, force F = \(\frac{m(v-u)}{t}\)

F = \(\frac{10(8-2)}{4}\)

= \(\frac{10 \times 6}{4}\)

= 15 N