Question

Calcium carbonate is decomposed on heating in the following reaction 

CaCO₃ → CaO + CO₂ 

1. How many moles of Calcium carbonate is involved in this reaction? 

2. Calculate the gram molecular mass of calcium carbonate involved in this reaction.

3. How many moles of CO₂ are there in this equation?

Answer 1

CaCO₃ → CaO + CO₂ 

1. 1 mole of CaCO₃ is involved in this reaction. 

2. Gram molecular mass of calcium carbonate CaCO₃ = (40 + 12 + 3 × 16) = 52 + 48 = 100 g 

3. 1 mole of CO₂ is in this equation.