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Which of the two elements would be more reactive, element A of atomic number = 36 or element B of atomic number = 19?

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The atomic number of element A is 36 and that of B is 19, by representing the atom in electronic configuration,

For A: 

K = 2 

L = 8 

M = 18 

N = 8 

The outermost shell N is complete with the octet so the element is stable in this state and will not be reactive because of the 0 valency and complete octet in the atom.

For B:

K = 2 

L = 8 

M = 9 

The valence electron in the element is 9 so it is not that stable, it will readily lose 1 electron in order to complete its octet of electrons and become stable.

So element B will be more reactive than the element A because of the complete octet in element A.

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