Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
618 views
in Physics by (22.9k points)
closed by

The driver of a train traveling at 40 ms-1 applies the brakes as a train enters a station. The train slows down at a rate of 2 ms-2. The platform is 400 m long. Will the train stop in time?

1 Answer

+1 vote
by (23.8k points)
selected by
 
Best answer

Given:

Initial Speed = u = 40 ms-1 

Acceleration = a = - 2 ms-2 (Retardation, hence negative) 

Final Speed = v 

Now, s = Distance train travels before stopping 

Now, we know from the equations of motion that,

v2 = u2 +2as

0 = 402 +2 \(\times\) (-2) \(\times\) s

4s = 1600

s = 400 m 

So, the train covers 400 m before stopping. 

Also, the length of platform = 400 m. 

So, the train stops in time.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...