Given:
Acceleration = a =2.5 ms-2
Time of Acceleration = t = 4 s
Initial velocity = u = 0 ms-1
Now, from the equations of motion we know that,
\(s = ut +\frac{1}{2}at^2\)
\(s =0\times4+\frac{1}{2}\times2.5\times4^2\)
\(s = 2.5\times8\)
s = 20 m
Hence, the girl travels 20 m in this time.
