Question

If 100 g of calcium carbonate on heating produces 44g of carbon dioxide, how much quicklime will be formed? Which law is followed for solving this problem?

Answer 1

Let the mass of quicklime formed is “x” 

CaCo₃ → CaO + CO₂

100g           x        44g

According to the law of conservation of mass, the sum of the masses of reactants is equal to the sum of the masses of products formed.

Hence, 100g = x + 44g

⇒ x = 100 – 44g 

⇒ x = 56 g 

Law of conservation of mass was followed for solving this problem.