In the first sample:
9g of hydrogen and 42g of nitrogen are present. According to the law of definite proportion, hydrogen and nitrogen are present in the ratio of 9:42 i.e., 3:14
In the second sample:
It is given that 5g of hydrogen is present along with nitrogen.
According to the law of constant proportion the second sample
must also contain hydrogen and nitrogen in 3:14 ratio. \(\frac{Amount\,of\,hydrogen}{Amount\,of\,nitrogen}\) = Ration
⇒ \(\frac{5}{Amount\,of\,nitrogen}\) = \(\frac{3}{15}\)
⇒ 14 × 5 = 3 × amt. of nitrogen
⇒ Amount of nitrogen = 70/3
⇒ Amount of nitrogen = 23.3g
Thus, the amount of nitrogen in the second sample is 23.3g.
