Given:
Mass of sodium carbonate = 212g
Sodium carbonate is Na2CO3
First, we need to calculate the number of moles of sodium carbonate we have in a 212g sample. To calculate this, we will ind the molar mass of sodium carbonate (Na2CO3 ):
⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen
⇒ 2 × 23 + 12 + 3 × 16
⇒ 46 + 12 + 48
⇒ 106g/mol
Thus, the molar mass of Na2CO3 is 106g/mol.
Now we will calculate total number of moles by applying the
formula given:
Number of moles = \(\frac{Mass\,of\,sodium\,carbonae}{Molar\,mass\,of\,sodium\,carbonate}\)
Number of moles = \(\frac{212g}{106g/mol}\)
⇒ 2 mol
Now, we know that every mole of Na2CO3 have 2 moles of Na+ ions.Hence, total moles of Na2CO3 is 4 moles
Number of ions present = 6.022 × 1023 × 4mol = 24.088 × 1023 ions