Question

In a chemical reaction 10.6 g of sodium carbonate reacted with 12g of ethanoic acid. The products were 4.4 g carbon dioxide, 1.8 g of water and sodium ethanoate. The mass of sodium ethanoate formed is 

A. 16.4 g B. 0.16 g C. 24 g D. 8.2 g

Answer 1

Let the mass of sodium etanoate is “x”g 

Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O

10.6g                12g                          xg               4.4g      1.8g      

Acoording to law of conservation of mass, 

Sum of masses of reactants = Sum of masses of products 

Hence, 10.6g +12.g = x + 4.4g +1.8g 

⇒ x = 16.4g 

Thus, the mass of sodium ethanoate formed is 16.4g