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An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at normal boiling point of the solvent. What is the molar mass of the solute?

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Vapour pressure of pure water at the boiling point (P°) = 1 atm 1.013 bar 

Vapour pressure of solution Ps = 1.004 bar 

M1 = 18 g mol-1 

M2 = ? 

Mass of solute = W2 = 2 g 

Mass of solution = 100 g 

Mass of solvent W1 = 98 g

Applying Raoult’s law for dilute solution

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