Molar mass of sucrose = C12H22O11
= 12× 12 + 1× 22 + 16 × 11 = 342g/mol
Number of moles = \(\frac{Mass\,of\,glucos}{Molar\,mass\,of\,sucrose}\)
⇒ Number of moles = \(\frac{3.42g}{342g/mol}\)
⇒ Number of moles = 0.01
Sucrose (C12H22O11) contains 11 oxygen atoms
⇒ 11 × 6.022 × 1023
For 0.01 moles of sucrose
⇒ 0.01 × 11 × 6.022 × 1023 = 6.6 × 10 22
Now, Molar mass of water = H2O = 2× 1 + 16 = 18g/mol
Number of moles =\(\frac{Mass\,of\,water}{Molar\,mass\,of\,water}\)
⇒ Number of moles = \(\frac{18g}{18g/mol}\)
⇒ Number of moles = 1
Sucrose (H2O) contains 1 oxygen atom = 6.022 × 1023
For 1 mole of water = 6.022 × 1023
Now, add the both values: 6.6 × 1022+ 6.022 × 1023 We get 6.68 × 1023 atoms.
Hence, the option (a) is correct.