Question

A cyclist is moving with a speed of 14 m/s. He starts accelerating with a rate of 6 m/s² and acquired the speed of 18 m/s. Calculate, what distance did he move in acquiring that speed?

Answer 1

Using the third equation of motion: v² – u² = 2

as 

where: 

s = distance covered =? 

v = final velocity = 18 m/s 

u = initial velocity = 14 m/s 

a = acceleration = 6 m/s² 

18² – 14² = 2×6× s

324 – 196 = 12 × s \(\frac{128}{12}\)= s

s = 10.67 m