Focal length of a convex lens f = 15 × 10-2 m
Weight of the object ho = 2 × 10-2 m
Let weight of the image be hv
Distance of the object u = 10 × 10-2 m
Distance of the image v = 15 × 10-2 m
We know
∴ v = -30 × 10-2 m
Distance of the image = 30 × 10-2 m
Hence a virtual image 6 × 10-2 m height is formed at a
distance of 30 × 10-2 m from the lens on the same side of the lens.