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Study the velocity-time graph and calculate.

(i) the acceleration from A to B. 

(ii) the acceleration from B to C. 

(iii) the distance covered in the region ABE. 

(iv) the average velocity from C to D. 

(v) the distance covered in the region BCFE.

1 Answer

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Best answer

(i) Acceleration from A to B = \(\frac{change\,in\,velocity}{change\,in\,time}\)= \(\frac{25-0}{3-0}\)= 8.33 m/s2 

(ii) Acceleration from B to C = \(\frac{15-25}{4-3}\)= -10 m/s2 

(iii) Distance covered in the region ABE = \(\frac12\)× base × height 

= × 3s × 25 m/s = 37.5 m 

(iv) Average velocity from C to D = \(\frac{initial\,velocity\,+\,final\,velocity}{2}\)

= \(\frac{15-0}{2}\)= 7.5 m/s

(v) Distance covered in the region BCFE =\(\frac12\) × sum of parallel sides x 

distance between them =\(\frac12\) × ( 25+15) × 1 = 20 m

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