**Answer: (C) =\(\frac{2}{5}\)**

**Let A: **Event that **Indian man is seated adjacent** to his wife.** **

**Let B: **Event that each **American is seated adjacent** to his wife.

Consider each couple as one entity. Thus, there are 5 entities to be arranged and husbands and wife can interchange their seats in 2! ways.

∴ \(P(A\,\cap\,B)\) = \(\frac{4!(2!)^5}{9!}\)

Next, consider each American couple as an entity. Thus, there are 6 entities to be arranged including the Indian and his wife.

∴ P(B) = \(\frac{5!(2!)^4}{9!}\)

### ∴ P(A/B) = \(\frac{P(A\,\cap\,B)}{P(B)}\) = \(\frac{4!(2!)^5}{5!(2!)^4}\) = \(\frac{2}{5}\)