Volume V0 = 105 cm3
Change in temperature ΔT = 40 – 25 = 15°C
Change in volume ΔV = 4 cm3
(i) The coefficient of cubical expansion is
\(a_V = \frac{Δ V}{V_0 Δ T}\)
\(a_V = \frac{4}{{10^5\times 15}}\) = 26.67 x 10-6 /°C
αV = 26.67 × 10-6 /°C
(ii) Coefficient of linear expansion is
aL = \(\frac{aV}{3}\)
\(a_L = \frac{26.67}{3}\times 10^{-6}\)
\(a_L\) = 8.89 x 10-6 /°C