Given, P1 = 76 cm Hg,
P2 = 7.6 cm of Hg
V1 = 30 m3, V2 = ?
T1 = 27 + 273 = 300 K
T2 = -54 + 273 = 219 K
By gas equation
\(\frac{P_1V_1}{T_1} = \frac{P_2 V_2}{T_2}\)
V2 = \(\frac{P_1V_1T_2}{T_1P_2}\) = \(\frac{76 \times 30 \times 219}{300 \times 7.6}\) = 219 m3
So increase in volume of gas = 219 – 30 = 189 m3.