Question

Using the ideal gas equation determine the value of universal gas constant. It is given that one gram, molecule of a gas at S.T.P occupies 22.4 litres.

Answer 1

Pressure P = 1.013 × 10⁵ pa

Volume V = 22.4 lit 

I = 22.4 × 10^-3 m³ 

Temperature T = 273 K 

For one mole of a gas 

PV = RT

∴ R = \(\frac{PV}{T}\)

 = \(\frac{1.013 \times 10^5 \times 22.4 \times 10^{-3}}{273}\)

= 8.31 J/mol/k