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in Physics by (51.5k points)
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If the far point of eye lens is 10 m, find power of the lens required to correct the defect.

1 Answer

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Best answer

Far point of the eye lens = v 

v = -10 m 

Object distance = u 

u = ∞ 

Lens Formula: 

\(\frac{1}{f}\,=\,\frac1v\,=\,\frac1u\)

\(\frac1f\,=\,\frac1{-10}\,-\,\frac1{∞}\)

Power of lens, P = 1/f 

= -10 D 

Hence the power of the lens required to correct the defect is -10 D. The lens used is a concave lens.

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