It is given that Power of Lens, P = 5.5 D

Now, since this lens is used for Myopic Eye, so it will be concave lens and hence the sign will be negative. So P = - 5.5 D

Now, for near vision power is to be increased by + 1 D.

Therefore, Power = -5.5 D + 1 D

= -4.5 D

Now, we know,

P = 1/f f = 1/p

f = 1/ 4.5

= - 22.22 cm

**Hence, Option C is correct**