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An electric iron draws a current of 0.5 A when the voltage is 220 volts. Calculate the amount of electric charge flowing through it in one hour.

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I = \(\frac{Q}{t}\)

Charge Q = ? 

Charge I = 0.5 A 

Time = 1 hour 

= 60 × 60 s

Q = It 

= 0.5 × 3600 

= 1800 C 

The amount of electric charge flowing = 1800 C

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