An equivalent of the given network is drawn in the relevant parts as follows: Resistance of the combination R1 and R2 is
Rs = 5 + 5 = 10Ω
Resistance of the combination R1, R2 and R3 is
The resistance of series combination \(R_{P_1}\) and R4 is \(R_{S_1}\) = 5 + 5 = 10Ω
Resistance of the combination \(R_{S_1}\) and R5 is
Resistance of the series combination \(R_{P_2}\) and R6 is
R\(S_2\) = 5 + 5 = 10Ω
Resistance of the combination \(R_{S_2}\) and R7 is
Resistance of the series combination \(R_{P_3}\) and R8 is
\(R_{P_3}\)= 5 + 5 = 10Ω
Resistance of the combination \(R_{S_3}\) and R9 is
Resistance of the series combination \(R_{P_4}\) and R6 is
\(R_{S_4}\) = 5 + 5 = 10Ω
Resistance of the combination \(R_{S_4}\) and R8 is
∴ Resistance between A and B is 5Ω