Given;
Refractive index of alcohol (μ) = 1.36.
Speed of light in vacuum = 3×108m/s.
Refractive index (μ) = \(\frac{c\,(speed\,of\,light\,in\,vaccum)}{v\,(speed\,of\,light\,in\,alcohol)}\)
⇒ 1.36 = \(\frac{3\,\times\,10^8}{speed\,of\,light\,in\,alcohol}\)
⇒ speed of light in alcohol = \(\frac{3\,\times\,10^8}{1.36}\)
∴ Speed of light in alcohol = 2.21 × 108m/s
Speed of light in alcohol with respect to air is 2.21 x 108ms-1