Question

A person who is sitting at a distance of 400 m from a source of sound is listening to a sound of 600 Hz. Find the time period between successive compressions from the source?

Answer 1

Distance of the observer = 400 m 

Frequency of sound n = 600 Hz 

Let velocity of sound be v = 330 \(\frac{m}{s}\)

Wavelength λ = \(\frac{v}{n}\) = \(\frac{330}{600}\)

= 55 × 10^-2 = 0.55 m

Distance between two successive compressions is \(\frac{λ}{2}\)

Time period successive compressions is = \(\frac{1}{\frac{λ}{2}}\)

= \(\frac{2}{λ}\) = \(\frac{2}{0.55}\)

T = \(\frac{2}{0.55}\) = 3.6363 second

Time period = 3.6363 second.