Given:
Area of the mirror = 1 cm2 ,
Power transmitted to the mirror = 10 Wcm-2 ,
Calculations: -
The average force is given by \(\frac{Δp}{Δt}\)
Since the surface is perfectly reflecting we can write Δp = 2\(\frac{Δt}{c}\)
So F = 2 \((\frac{ΔE}{cΔt})\) = 2 \(\frac{p}c\)
=2 \(\frac{10\times10^4\times1\times10^{-4}}{3\times10^8}\)
= \(\frac{20}{3}\)x 10-8 N
= 6.7 x 10-8 N