Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
36.4k views
in Arithmetic Progression by (44.5k points)
closed by

Solve for x

1 + 6+11 + 16 +...+ x = 148

1 Answer

+1 vote
by (55.5k points)
selected by
 
Best answer

Here, a = 1, d = 6 – 1 = 5 and Sn = 148

⇒ 296 = n[5n – 3]

⇒ 5n2 – 3n – 296 = 0

⇒ 5n2 – 40n + 37n – 296 = 0

⇒ 5n(n – 8) + 37(n – 8) = 0

⇒ (5n + 37)(n – 8) = 0

⇒ 5n + 37 = 0 or n – 8 = 0

⇒ n = -37/5 or n = 8

But n = -37/5 is not a positive integer.

∴ n = 8

⇒ x = a8 = a + 7d = 1 + 7 × 5 = 1 + 35 = 36

Hence, x = 36

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...