Let P and Q be the points of trisection at AB. i.e., AP = PQ = QB
Therefore, P divides AB internally in the ratio 1 : 2. Therefore, the coordinates at P, by applying the section formula, are
Now, Q also divides AB internally in the ratio 2 : 1,
So, the coordinates at Q are
Therefore, the coordinates of the points at trisection of the line segment joining A and B are (-1, 0) and (-4, 2).