Given: a2 = 2 and a4 = 8 and n = 51
We know that,
a2 = a + d = 2 …(i)
and a4 = a + 3d = 8 …(ii)
Solving the linear equations (i) and (ii), we get
a + d – a – 3d = 2 – 8
⇒ -2d = -6
⇒ d = 3
Putting the value of d in eq. (i), we get
a + 3 = 2
⇒ a = 2 – 3 = -1
Now, we have to find the sum of first 51 terms.
⇒ S51 = 51 [-1 + 25 × (3)]
⇒ S51 = 51 [74]
⇒ S51 = 3774