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Organic compounds A and B are isomers with the molecular formula C2H6O (A) liberates H2 gas when it reacts with metallic sodium whereas (B) does not. Compound (A) reacts with ethanoic acid and forms a fruity smelling compound (C). Identify A, B and C and explain the reactions.

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(A) and (B) are compounds with same molecular formula C2H6O. 

(A) reacts with metallic Na and liberates H2 ↑ 

∴ (A) is ethanol [CH3CH2OH]

(B) is methoxy methane [CH3OCH3]

(A) reacts with ethanoic acid and forms ester.

(A) Ethanol, CH3CH2OH 

(B) Methoxy methane, CH3OCH3 

(C) Ethyl ethanoate, CH3COOC2H5

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