Answer: (c) =80080 cu.cm.
Bucket is a frustum of a right circular cone.
Here, R = 35 cm, r = 14 cm, h = 40 cm.
Volume of frustum of cone = \(\frac{\pi h}{3}(R^2+r^2+Rr)
\)
= \(\frac{22}{7}\times \frac{40}{3}(35^2+14^2+35\times 14)\)
= \(\frac{880}{21}(1225+196+490)
\)
= \(\frac{880}{21} \times 1911\)
= 80080 cu. cm.