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If x sin3 θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ, then prove that x2 + y2 = 1.

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x sin3 θ + y cos3 θ= sinθ cosθ ; x sinθ y cosθ.

x (sinθ) [sin2 θ + cos2 θ] = sinθ cosθ

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