A and B represent points on the bank on opposite sides at the river, so that AB is the width of the river. P is a point on the bridge at a height of 3m i.e., DP = 3 m. We are interested to determine the width at the river which is the length at the side AB of the ΔAPB.
Now, AB = AD + DB
Also, in right ΔPBD,
B = 45°
So, BD = PD = 3 m
Now, AB = BD + AD
= 3 + 3√3 = 3(1 + √3)m
Therefore, the width at the river is 3(√3 + 1)