Why is the weight of an object on the moon 1/ 6 th its weight on the earth?

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sforrest072 · Answer 1 · 2017-10-14T00:44:02+0000

Let ME be the mass of the Earth and m be an object on the surface of the Earth. Let R_E be the radius of the Earth. According to the universal law of gravitation, weight W_E of the object on the surface of the Earth is given by,

Let MM and RM be the mass and radius of the moon. Then, according to the universal law of gravitation, weight WM of the object on the surface of the moon is given by: