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Draw a schematic diagram of an electric circuit consisting of battery of five 2V cells, a 20 Ω resistor, a 30 Ω resistor, a plug key, all connected in series. Calculate the value of current flowing through the 20 Ω resistor and the power consumed by the 30 Ω resistor.

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The schematic diagram is shown below

Current Flowing Through 20Ω resistor

Current (I) = \(\frac{Voltage (V)}{Resistance (R)}\)

⇒ Current = \(\frac{10}{20}=\frac12\) = 0.5 A

Hence the current flowing is 0.5 Ampere. 

Power consumed by the 30 Ω resistor 

Power = Voltage × current. 

Given Voltage = 10V; current = 0.5A 

⇒ Power = 10 × 0.5 = 5W 

Hence power consumed by 30 Ω resistor is 5W.

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