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The brakes applied to a car produce an acceleration of 6 ms-2 in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance traveled during this time.

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We have been given a = – 6 ms-2

t = 2s and v = 0 

From the equation of motion, 

v = u + at 

0 = u + (- 6 × 2) .

0 = u – 12 

∴ u = 12 ms-1

s = ut + 1/2 at2 

= (12 × 2) + 1/2 (- 6 × 2 × 2). 

= 24 – 12 = 12m 

Thus, the car will move 12 m before it stops after the application of brakes.

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