Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
26.3k views
in Statistics and Probability by (47.8k points)
closed by

Three fair coins are tossed together. Find the probability of getting

(i) all heads

(ii) atleast one tail

(iii) atmost one head

(iv) atmost two tails

1 Answer

+2 votes
by (47.4k points)
selected by
 
Best answer

Three fair coins are tossed together

Sample spade = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

n(S) = 8

(i) Let A be the event of getting all heads

A = {HHH}

n(A) = 1

P(A) = \(\frac{n(A)}{n(S)}=\frac{1}{8}\)

(ii) Let B be the event of getting atleast one tail.

B = {HHT, HTH, HTT, THH, THT, TTH, TTT}

n(B) = 7

P(B) = \(\frac{n(B)}{n(S)}=\frac{7}{8}\)

(iii) Let C be the event of getting atmost one head

C = {HTT, THT, TTH, TTT}

n(C) = 4

P(C) = \(\frac{n(C)}{n(S)}=\frac{4}{8}=\frac{1}{2}\)

(iv) Let D be the event of getting atmost two tails.

D = {HTT, TTT, TTH, THT, THH, HHT, HTH}

n(D) = 7

P(D) = \(\frac{n(D)}{n(S)}=\frac{7}{8}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...