Fewpal
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What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m). 

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1 Answer

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According to the universal law of gravitation, gravitational force exerted on an object of mass m is given by 

= / 2  

Where, 

Mass of Earth, M = 6 × 1024 kg 

Mass of object, m = 1 kg 

Universal gravitational constant, G = 6.7 × 10−11 Nm2 kg−2 

Since the object is on the surface of the Earth, 

r = radius of the Earth (R) 

r = R = 6.4 × 106

Therefore, the gravitational force 

= / 2 = 6.7 × 10−11 × 6 × 1024 × 1 / (6.4 × 106) 2 = 9.8  

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