What is the solution of 19th question

Question

If |(a,a²,1+a³),(b,b²,1+b³)(c,c²,1+c³)|= 0 and the vector A =(1,a,a²), B=(1,b,b²), C=(1,c,c²) are non-coplanar, then the value of abc equal to

19

Answer 1

Since the vectors (1,a,a²),(1,b,b²),(1,c,c²) are non-coplanar, we have

Then (1) gives abc= −1.