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If |(a,a2,1+a3),(b,b2,1+b3)(c,c2,1+c3)|= 0 and the vector A =(1,a,a2), B=(1,b,b2), C=(1,c,c2) are non-coplanar, then the value of abc equal to


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Since the vectors (1,a,a2),(1,b,b2),(1,c,c2) are non-coplanar, we have

Then (1) gives abc= −1.

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