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If n is an odd integer, then (1+I)6n+(1-i)6n is equal to

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If n is an odd integer, then (1+I)6n+(1-i)6n is equal to

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(1+i)6n+(1-i)6n

= (1+2i+i2)3n+(1-2i+i2)3n

= (1+2i-1)3n+(1-2i-1)3n

= (+2i)3n+(-2i)3n

 = +(2i)3n-(2i)3n

= 0

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