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in Statistics and Probability by (47.4k points)
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A coin is tossed thrice. Find the probability of getting exactly two heads or at least one tail or two consecutive heads.

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Three coins tossed simultaneously.

S = { HHH, TTT, HHT, TTH, HTH, THT, HTT, THH}

n(S) = 8

Happening of getting exactly two heads be A.

A= {HHT, HTH, THH}

n(A) = 3

P(A) = \(\frac{n(A)}{n(S)} = \frac{3}{8}\)

Event of getting at least one tail be B.

∴ B = {TTT, HHT, TTH, HTH, THT, HTT, THH}

n(B) = 7

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