Question

If A, B, C are any three events such that probability of B is twice as that of probability of A and probability of C is thrice as that of probability of A and if P(A ∩ B) = \(\frac{1}{6}\), P(B ∩ C) = \(\frac{1}{4}\), P(A ∩ C) = \(\frac{1}{8}\), P(A ∪ B ∪ C) = \(\frac{9}{10}\), P(A ∩ B ∩ C) = \(\frac{1}{15}\), then find P(A), P(B) and P(C)?

Answer 1

P(B) = 2P(A)

P(C) = 3P(A)