Answer: (b) = 523.54 cm3
Volume of wood in the entire stand = Volume of cuboidal stand – Volume of 4 conical depressions
= l × b × h – 4 × \(\frac{1}{3}\) πr2h
= 15 × 10 × 3.5 - 4 × \(\frac{1}{3}\) × \(\frac{22}{7}\) × (0.5)2 × 1.4
= 525 - 1.46 cm3
= 523.54 cm3