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in Magnetism and Electromagnetism by (52.2k points)
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A conductor of length 50 cm carrying a current of 5 A is placed perpendicular to a magnetic field of induction 2 × 10-3 T. Find the force on the conductor

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by (54.5k points)
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Best answer

Force on the conductor = ILB 

= 5 × 50 × 10-2 × 2 × 10-3 

= – 5 × 10-3 N

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