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A concave mirror produces three times magnified real image of an object placed at 7 cm in front of it. Where is the image located? (21 cm in front of the mirror)

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Given: hi = 3h0 

u = 7 cm

1. m = \(\frac{h_i}{h_0}\) ⇒ \(\frac{3h_0}{h_0}\)

∴ m = 3.

2. m = \(-\frac{v}{u}\)

v = - m x u

= -3 x 7 cm = 21 cm.

Hence, Real, inverted and magnified image will be formed at 21 cm in front of the mirror

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