Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
823 views
in Chemistry by (49.3k points)
closed by

Complete the following reactions:

(I) CH3COOH + NaOH →

(ii) 

(iii) CH3OH + O\(\underset{MoO_3}{\stackrel{873-923 k}{\longrightarrow}}\)

(iv) CH2 = CH2 +Br →

(v) CH3COOC2H5 + NaOH →

(vi) CH2 = CH2 + H2\(\overset{H_2SO_4}\longrightarrow\)

1 Answer

+1 vote
by (46.3k points)
selected by
 
Best answer

(i) This is an example of neutralization reaction 

CH3COOH + NaOH → CH3COONa + H2

(iii) Alcohols will get oxidised to acids in the presence of MoO3 which is an oxidising agent. In this case, methanol (CH3OH) gets oxidised to methanoic acid (HCOOH). 

CH3OH +O2  \(\underset{MoO_3}{\stackrel{873-923 k}{\longrightarrow}}\) HCOOH

(iv) CH2 = CH2 + Br → CH2Br—CH2Br 

This is an example of addition reaction

(v) CH3COOC2H5 + NaOH → CH3COOH + C2H5OH 

This is an example of saponification reaction and is used in the preparation of soaps. 

(vi) CH2 = CH2 +H2\(\overset{H_2SO_4}\longrightarrow\) CH3-CH2-OH

This is an addition reaction, where H+ is added to one of the carbon and OH- is added to the other carbon. 

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...