Whenever we have to find total displacement from a velocity time graph we find the area under the curve.
In the figure we clearly see
• Two triangles ABF & DCE having area A1 & A2 respectively
• A rectangles BEIF having area A3 .
A1 =\(\frac{(2-0)\times(5-0)}{2}\) = 5
A2 =\(\frac{(10-5)\times(10-6)}{2}\) = 10
A3 = (5-0)x(10-2) = 40
Total area under the curve = A1 + A2 + A3
= 5 + 10 + 40 = 55
Hence total displacement = 55 m
