**Given: **

Mas of bullet = 10g

Velocity of bullet = 150ms^{-1}

Mass of pistol = 2 kg

Due to the law of conservation of momentum the momentum of the bullet is equal to the recoil of the gun. So the sum of the momentum of both the objects is equal to zero.

M_{b}V_{b} = –M_{g}V_{g} , Now,

V_{g }= \(-\frac{M_bV_b}{M_g}\) = \(-\frac{0.01\times150}{2}\) = 0.75ms^{-1}