Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.2k views
in Physics by (46.3k points)
closed by

State and prove the law of conservation of linear momentum.

1 Answer

+1 vote
by (49.3k points)
selected by
 
Best answer

According to the law of conservation of momentum 

When two or more bodies act upon each other their total momentum remains constant provided no external forces are acting 

•So, Momentum is never created or destroyed. 

•When this law is applied for a collision between two bodies, the total momentum of the colliding bodies before the collision is equal to the total momentum after the collision. 

•We can apply this law for a collision between two vehicles. This law is applicable for all types of collisions. 

•Consider two particles say A and B of mass m1 and m2 collide with each other and forces acting on these particles are only the ones they exert on each other. 

•Let u1 and v1 be the initial and final velocities of particle A and similarly, u2 and vfor particle B. Let the two particles be in contact for a time t. 

So, Change in momentum of A = m1 (v1-u1) Change in the momentum of B = m2 (v2-u2

•During the collision, let A impart an average force equal to FBA on B and let B exert an average FAB on A. 

We know that from third law of motion FBA = FAB eq. (4) 

FBA = m2 x a2\(\frac{m_2(v_2-u_2)}{t}\)

 FAB = m1 x a1 = \(\frac{m_1(v_1-u_1)}{t}\)

Canceling t on both sides and rearranging the equation we get m1 u1 + m2 u2 = m1 v1 + m2 v2 eq.(5) 

Now, m1 u1 + m2 u2 represents the total momentum of particles A and B before collision and m1 v1 + m2 v2 represents the total momentum of particles after the collision. This means that 

Total momentum before collision = total momentum after the collision 

•Equation 5 which m1 u1 + m2 u2 = m1 v1 + m2 v2, is known as the law of conservation of momentum.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...